How Can Gravity Be Simulated In An Orbiting Space Station
Question: A force is exert on an object without doing work on the object
Answer: so if no distance moved, there is no work done.
Ex. pushing on a wall
W=Fd
Question: If both sacks in the preceding question are lifted their respective distances in the same time, how does the power required for each compare?
Answer: Since the work done is the same, power is the same. P=w/t P=Fd/t
Question: Two cars are raised to the same elevation on service-station lifts. If one car is twice as massive as the other, how do their pontential energies compare?
Answer: the car with twice the mass will have twice the potential energy. PE=mgh PE~m
Question: A moving car has kinetic energy. If it speed up until it is going four time as fast, how much kinetic energy does it have in comparison?
Answer: KE~V^2
If the new V=4 times, V=4, KE=(4)^2=16 times the original KE.
Question: Compared with some original speed, how much work must the brakes of a car supply to stop a car that is moving four times as fast? How will the stopping distance compare?
Answer: a)
, W=1/2m(V)^2, W~V^2, W=(V)^2
if new V=4 times, W=(V)^2=(4)^2= 16 times the original work.
b)
,d=(V)^2=(4)^3=16 times the original distance.
Question: An apple haging from a climb has potential energy because of its height. If it falls, what becomes of this energy just before it hits the ground? When its hit the ground?
Answer: As the apple falls, PE becames KE
when it hits the ground KE becomes force.
(W=KE, W=Fd, KE=1/2mv^2, Fd=1/2mv^2)
Question: Can a machine multiply input force? Input distance? Input energy?
Answer: A machine can multiply input force and distance but not energy.
Question: A force of 50N is applied to the end of a lever, which is moved a certain distance. If the other end of the lever moves one-third as far, how much force can it exert?
Answer: Fd=fD, d=1, d=1/3, f=50N, F=?
F=fD/d=50N(1)/1/3=150N
Question: What is the efficiency of a machine that miraculously converts all the input energy to useful output energy?
Answer: An automobile.
Efficiency=output/input=100/100*100= 100% efficient.
Question: If a moving object doubles its speed, how much more momentum does it have? How much more energy?
Answer: a)momentum=mv, momentum~velocity if v doubles, momentum double.
b) KE=V^2=(2)^2=4 times the original KE.